2x^2-3x-1=-2x^2

Solution for 2x^2-3x-1=-2x^2 equation:

2x^2-3x-1=-2x^2

We move all terms to the left:

2x^2-3x-1-(-2x^2)=0

We get rid of parentheses

2x^2+2x^2-3x-1=0

We add all the numbers together, and all the variables

4x^2-3x-1=0

a = 4; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·4·(-1)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-5}{2*4}=\frac{-2}{8}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+5}{2*4}=\frac{8}{8}
=1
$